The perimeter of the rectangle is 56cm. Find its area if the width is 6 times less than the length.

The perimeter of the rectangle corresponds to the formula:

P = 2a + 2b.

We know that this value for such a figure is 56 cm, and its length is 6 times longer. Let’s make an equation and define the dimensions of the rectangle:

2x + 2 * 6x = 56. Let’s perform actions with the coefficients of the variable on the left side of the equation:

14x = 56. To find the second factor, divide the product by the first:

x = 56: 14 = 4.

Therefore, width = 4 cm and length = 4 * 6 = 24 cm.



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