The perimeter of the rectangle is 58 cm. The length is 5 cm longer than the width. What are the sides.

According to the condition of the task, we will compose an equation, where we take the smallest side of the rectangle for x, the length for x + 5, and the sum of all sides = 58 cm.

The perimeter is calculated using the formula:

P = 2a + 2b. Substitute the values and get:

2 * (x + 5) + 2x = 58. Let’s open the brackets:

2x + 10 + 2x = 58. Let’s perform actions with the coefficients of the variable on the left side of the equation, and transfer the number to the right, changing the sign to the opposite:

4x = 58 – 40 = 18. To find the second factor, divide the product by the first:

x = 18: 4 = 4.5.

Therefore, width = 4.5 cm and length = 4.5 + 5 = 9.5 cm.