The perimeter of the rectangle is 6 dm 8cm one of its sides is 1dm 6cm smaller than the adjacent

| July 4, 2021 | education

The perimeter of the rectangle is 6 dm 8cm one of its sides is 1dm 6cm smaller than the adjacent side. find the encourage rectangle.

1. Let’s translate the value of the perimeter of the rectangle and the difference between its two sides in cm:
Perimeter 6 dm 8 cm = 68 cm.
Side difference = 1 dm 6 cm = 16 cm.
2. Let one of the adjacent sides be equal to y, then the other is equal to y + 16 cm. Let us write the expression for the perimeter, doubling the sum of its adjacent sides, we get the equation, we find y:
2 * (y + y + 16) = 68,
2 * (2y + 16) = 68,
4y + 32 = 68,
4y = 68 – 32,
4y = 36,
y = 36/4,
y = 9 cm.
3. Find the adjacent side of the rectangle:
9 + 16 = 25 cm.
4. Find the product of the adjacent sides of the rectangle, which forms its area:
Area = 9 * 25 = 225 cm2.
Answer: the area of the rectangle is 225 cm2.



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