The perimeter of the rectangle is 6 in 8 cm, one on its sides is 1 in less than the adjacent one. Find the area of the rectangle.

It is known that the perimeter of a rectangle is P = 6 dm 8 cm, and one of the sides is 1 dm less than the other.

It is necessary to calculate the area of ​​the rectangle.

Let’s denote the smaller side by A, then the larger side will be equal to A + 1 dm.

Let’s write a formula for the perimeter of a rectangle, expressing P through dm.

6 dm 8 cm = 6.8 dm.

6.8 dm = * 2 (A + A + 1 dm).

4A + 2 dm = 6.8 dm.

A = (6.8 dm – 2 dm) / 4.

A = 1.2 dm.

Thus, we have found the smaller side of the rectangle 1.2 dm.

Now let’s calculate the big side.

1.2 dm + 1 dm = 2.2 dm.

It remains to determine the area of ​​the rectangle by multiplying the found sides.

1.2 dm * 2.2 dm = 2.64 dm2.

As a result, we have the area of ​​the rectangle equal to 2.64 dm2.

Answer: 2.64 dm2.