The perimeter of the rectangle is 64 cm, and the width is 18 cm. How many cm is the width of this rectangle

The perimeter of the rectangle is 64 cm, and the width is 18 cm. How many cm is the width of this rectangle less than its length?

P = 2a + 2b, a – width, b – length.

2a = P – 2b

2a = 64 – 2 * 18

2a = 64 – 36

2a = 28

a = 14 – width.

Now we find out how many cm the width of this rectangle is less than its length:

18 cm – 14 cm = 4 cm.

Answer: The width of this rectangle is less than its length by 4 centimeters.



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