The perimeter of the rectangle is 66 dm. The length of one side is 3/11 of the perimeter. Find the area of the rectangle.

To solve this problem, remember that the perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. We calculate the length, knowing that it is 3/11 of the perimeter, that is, from 66 dm. To find a part of a number, you need to multiply this number by a part.
3/11 * 66 = 6 * 3 = 18 dm.
Let’s calculate the width of the rectangle.
2 * (x + 18) = 66;
x + 18 = 66/2;
x + 18 = 33;
x = 33 – 18;
x = 15 dm.
The area of a rectangle is equal to the product of its length and width. S = a * b, where a is the length and b is the width.
S = 15 * 18 = 270 dm ^ 2.
Answer: 270 dm ^ 2.