# The perimeter of the rectangle is 68 cm, its length is 24 cm.

**The perimeter of the rectangle is 68 cm, its length is 24 cm. The side of the square is equal to the width of the rectangle. find the perimeter and area of the square.**

To solve this problem, remember that the perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let’s calculate what the width of the rectangle is.

68 = 2 * (24 + x);

24 + x = 68/2;

24 + x = 34;

x = 34 – 24;

x = 10 m.

To solve this problem, remember that the perimeter of a square is equal to the sum of the lengths of all its four sides. Since all sides of a square are equal, its perimeter P = 4a, where a is its side. The area of a square is equal to the square of its side. S = a ^ 2.

P = 4 * 10 = 40 meters.

S = 10 * 10 = 100 sq.m.

Answer: 40 m, 100 sq.m.