The perimeter of the rectangle is 76 cm. Find its area if the width is less than the length by 4 cm.

Let’s denote the length of this rectangle through x.
According to the condition of the problem, the width of this rectangle is less than its length by 4 cm, therefore, the width of this rectangle is x – 4 cm.
It is also known that the perimeter of the rectangle is 76 cm, therefore, we can make the following equation:
2 * (x + x – 4) = 76.
We solve the resulting equation:
2 * (2x – 4) = 76;
2x – 4 = 76/2;
2x – 4 = 38;
2x = 38 + 4;
2x = 42;
x = 42/2;
x = 21 cm.
Knowing the length of the rectangle, we find its width:
x – 4 = 21 – 4 = 17 cm.
Find the area S of a given rectangle as the product of the length and width of a given rectangle:
S = 21 * 17 = 357 cm².
Answer: the area of ​​this rectangle is 357 cm².