The perimeter of the rectangle is 96 m, and it is 8 times larger than one of the sides of the rectangle. Find the area of the rectangle.

Let us denote the lengths of the sides of this rectangle through x and y.
According to the condition of the problem, the perimeter of this rectangle is 96 m, therefore, the following relation holds:
2 * (x + y) = 96.
It is also known that the perimeter of a given rectangle is 8 times larger than one of the sides of the rectangle.
Let this side be side x.
In this case, we can make the following ratio:
x * 8 = 96.
We solve the resulting equation:
x = 96/8;
x = 12 m.
Substituting the found value of x into the ratio 2 * (x + y) = 96, we get:
2 * (12 + y) = 96.
We solve the resulting equation:
12 + y = 96/2;
12 + y = 48;
y = 48 – 12;
y = 36 m.
Knowing the lengths of the sides of a given rectangle, we find its area S:
S = 12 * 36 = 432 m².
Answer: the area of ​​this rectangle is 432 m².