The perimeter of the rectangular area is 60 m, and the area is 200 m2. Find his side.

Let the length of the section be a and the width b. To find the perimeter and area of a rectangular section, you can write the following equalities:

P = 2 (a + b) = 60;

S = ab = 200

Let us express the length in terms of area and width in the second expression and substitute it into the first expression:

a = 200 / b;

2 (200 / b + b) = 60.

Let’s expand the brackets, simplify and solve the equation:

400 / b + 2b = 100;

400 + 2b2 = 60b;

2b2 – 60b + 400 = 0;

√D = √ (3600 – 4 * 2 * 400) = √ (3600 – 3200) = 20

b1 = (60 + 20) / 4 = 20

b2 = (60 – 20) / 4 = 10

From here we find the other side:

a1 = 200 / b1 = 200/20 = 10;

a2 = 200 / b2 = 200/10 = 20.

Answer: the sides of the rectangle are 20 cm and 10 cm.