The perimeter of the rectangular section is 2500m. The width of the site is 150m less than its length.

The perimeter of the rectangular section is 2500m. The width of the site is 150m less than its length. Find the area of the lot.

1) Find the width of the site. Let’s compose an equation according to the condition of the problem, where:

X is the width of the section;

X + 150 – section length;

2500 – perimeter.

(X + X + 150) * 2 = 2500;

4X + 300 = 2500;

4X = 2500 – 300;

4X = 2200;

X = 2200/4;

X = 550 m section width.

2) We find out how long the section has, if it is known that it is 150 m more than its width.

550 + 150 = 700 m length

3) Find the area of the site if it is known that its length is 700 m, and its width is 550 m.

S = 700 * 550 = 385000 sq. M.

Answer: the area of the site is 385,000 sq. M.