The perimeter of the rhombus is 40 cm, and one of its diagonals is 12 cm. Find the second diagonal of the rhombus.

40: 4 = 10cm – each side of the ABСD rhombus tr. ABO and BОС are equal; AB, BС-hypotenuses ==> AO = OС = 5 AC = 5 * 2 = 10cm (point O is divided in half ==> multiply by 2) Answer: 10



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