The perimeter of the rhombus is 48, and the distance from the intersection of the diagonals of the rhombus

The perimeter of the rhombus is 48, and the distance from the intersection of the diagonals of the rhombus to the side is 4. Find the area of the rhombus.

1) Since this is a rhombus, all its sides are equal, therefore a = P / 4
a = 48/4 = 12
2) All triangles into which the rhombus is divided by the diagonals are equal in two legs, therefore from the area are also equal and equal to 1 / 2a * h, where h is the distance from the point of intersection of the diagonals to the side of the rhombus.
3) Sromba = 4 * 1 / 2a * h = 2 * a * h = 2 * 4 * 12 = 96
Answer: 96