The perimeter of the square ABCD is 28 cm and its area was calculated.

since all sides of the square are equal, and the perimeter is 28, you can find the length of one side
for this 28/4 = 7 cm
the area of a square is equal to the square of its side
S = a ^ 2
S = 7 ^ 2 = 49 cm ^ 2
Answer: the area of the ABSD square is 49 cm ^ 2



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