The perimeter of the square and rectangle is 56 cm each. The width of the rectangle is 7 times less than

The perimeter of the square and rectangle is 56 cm each. The width of the rectangle is 7 times less than the side of the square. find the area of a rectangle.

Let us express the measurement of a square, provided that its perimeter is 56 cm, from the formula:
If P = 4a, therefore: a = P: 4 = 56: 4 = 14 cm.

The sum of all sides of the rectangle is the same = 56 cm, and its width is 7 times less, which corresponds to:
14: 7 = 2 cm.

Find the length by expressing it from the formula:

P = 2a + 2b. To find the first term, subtract the second from the sum:

2a = P – 2b = 56 – 2 * 2 = 56 – 4 = 52. The second factor corresponds to the partial product of the first:

a = 52: 2 = 26 cm.

Let’s calculate the area of the rectangle:
S = a * b = 26 * 2 = 52 cm².