The perimeter of the square and the rectangle are the same. The area of the square is 36 A.

The perimeter of the square and the rectangle are the same. The area of the square is 36 A. The length of the rectangle is 5 times the width. Find the area of the rectangle.

As you know, 1 a = 100 m², which means that the area of this square is 3600 m².

This means that the side of this square is 60 m:

60 * 60 = 3600.

Therefore, the perimeter of this square is:

P = 4 * 60 = 240 (m).

Suppose that the width of the rectangle is x m, then, according to the condition of the problem, the length is 5 * x m.

Now let’s find what the sides of the rectangle are equal to:

2 * (x + 5 * x) = 240,

6 * x = 120,

x = 120: 6,

x = 20 (m) – the width of the rectangle.

20 * 5 = 100 (m) – the length of the rectangle.

The area of the rectangle is:

S = 20 * 100 = 2000 (m2) = 20 (a).