The perimeter of the square is 12.4 dm. One of its sides changed by 2.3 dm.

The perimeter of the square is 12.4 dm. One of its sides changed by 2.3 dm. Find the perimeter of the resulting rectangle.

Find the initial length of each side of the square.

We divide the specified perimeter into 4 equal parts.

12.4 / 4 = 3.1 dm.

In the event that the side was increased by 2.3 dm, it was:

3.1 + 2.3 = 5.4 dm.

So the perimeter of the resulting rectangle has become:

2 * (3.1 + 5.4) = 2 * 8.5 = 17 dm.

If the side was reduced by 2.3 dm, then its length was:

3.1 – 2.3 = 0.8 dm.

Thus, the perimeter of the rectangle was:

2 * (3.1 + 0.8) = 2 * 3.9 = 7.8 dm.

Answer: The perimeter is 17 or 7.8 dm.