The perimeter of the square is 16 cm. Find the area of a rectangle whose width is equal to the side

The perimeter of the square is 16 cm. Find the area of a rectangle whose width is equal to the side of the square and the length is 6 cm.

Let the perimeter of the square be P = 16 cm and its side A is the side of the rectangle, the second side of which is 6 cm. It is necessary to calculate the area of the rectangle.

Let’s first calculate the side of the square.

P = 4 * A.

A = P: 4.

A = 16 cm: 4.

A = 4 cm.

Thus, one side of the rectangle is equal to the side of the square and is equal to 4 cm.

It remains to calculate the area of the rectangle S by multiplying both sides of it by each other.

S = 4cm * 6cm.

S = 24 cm2.

Answer: the area of the rectangle is 24 cm2.