The perimeter of the square is 16 cm. One rectangle was folded out of three such squares.
| July 21, 2021 | education
The perimeter of the square is 16 cm. One rectangle was folded out of three such squares. Find the perimeter and area of this rectangle.
To solve the problem, it is necessary to determine the length of the side of the square.
Since the perimeter is equal to twice the sum of the two sides of the square, we get:
16/2 = 8 cm.
8/2 = 4 cm (the length of the side of the square).
In this case, when adding 3 squares, the length of the rectangle will be equal to the sum of three equal sides.
4 + 4 + 4 = 12 cm.
The width of the rectangle will be 4 cm.
The perimeter of the rectangle will be:
2 * (4 + 12) = 2 * 16 = 32 cm.
The area of the rectangle will be:
4 * 12 = 48 cm ^ 2.
Answer: Perimeter 32 cm, area 48 cm ^ 2.
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