The perimeter of the square is 20 cm. From two such squares they made a rectangle.

The perimeter of the square is 20 cm. From two such squares they made a rectangle. Find the perimeter and area of this rectangle.

1) Let X be the side of the square.

2) Based on the condition of the problem, we compose the equation:

2 (2 X) = 20;

4 X = 20;

X = 5;

3) Based on the condition of the problem, the sides of the rectangle will be equal:

The length will be equal to: 2 * 5 = 10 cm;

The width will be: 5 cm;

4) The perimeter of the rectangle will be:

2 (10 + 5) = 2 * 15 = 30 cm;

5). The area of the rectangle will be equal to:

5 * 10 = 50 cm ^ 2;

Answer: The perimeter of the rectangle will be 30 cm, the area of the rectangle will be 50 cm ^ 2.



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