The perimeter of the square is 28 m. Find the area of a rectangle whose width

The perimeter of the square is 28 m. Find the area of a rectangle whose width is equal to the side of the square. And the length is 2 times the width?

1) Since the perimeter of the square is known in the problem statement, it is possible to calculate the value of its side: a = P: 4 = 28: 4 = 7 (m). This value (according to the problem statement) will be the width of the rectangle.

2) Find out what the length of the rectangle is. To do this, we will increase its width by 2 times: 7 · 2 = 14 (m);

3) Apply the formula for finding the area of rectangles and calculate it: S = a · b = 7 · 14 = 98 (m ^ 2).

Answer: S = 98 m ^ 2.