The perimeter of the square is 64 cm. A rectangle was folded from two such squares

| August 4, 2021 | education

The perimeter of the square is 64 cm. A rectangle was folded from two such squares. Find the length, width, perimeter, and area of this rectangle.

To solve this problem, remember that a square is a quadrangle. in which all four sides are equal. Knowing that the perimeter of the square is 64 cm, we calculate the length of its side.
a = 64/4 = 16 cm.
Then the width of the rectangle is 16 cm, and its length is 16 * 2 = 32 cm. The area of the rectangle is equal to the product of length and width. S = a * b, where a is the length and b is the width.
S = 16 * 32 = 512 cm ^ 2.
The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width.
P = 2 * (16 + 32) = 2 * 48 = 96 cm.
Answer: 32 cm, 16 cm, 96 cm, 512 cm ^ 2.



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