The perimeter of the square is 64 cm. Find the length of a rectangle that is 4 cm wide and 8

The perimeter of the square is 64 cm. Find the length of a rectangle that is 4 cm wide and 8 times smaller than the area of the square.

1) We calculate the length of the side of the square a, if its perimeter is 64 cm: Pkv = 4 * a, a = 64/4 = 16 cm.

2) Calculate the area of the square at a = 16 cm: Sq = a * a, Sq = 16 * 16 = 256 cm2.

3) Let us calculate the area of a rectangle if it is known that it is 8 times less than the area of a square: Spr = Sq / 8, Spr = 256/8 = 32 cm2.

4) Calculate the length of the rectangle c, if the width b is 4 cm, and the area of the rectangle is 32 cm2: Spr = b * c, c = Spr / b = 32/4 = 8 cm.

Answer: the length of the rectangle is 8 cm.