The perimeter of the square is 64 cm. Find the length of the rectangle.

The perimeter of the square is 64 cm. Find the length of the rectangle. The width of which is 4 cm, and the area is 2 times less than the area of the square.

Let’s solve this task in steps and explain each of them in detail.

1) 64: 2 = 32 cm ^ 2 – the area of the square, since it is 2 times larger than the area of the rectangle, and the area of the rectangle is 64 cm ^ 2;

2) 4 * 2 = 8 centimeters – the sum of the two sides of the rectangle, since its width is 4 centimeters;

3) 32 – 8 = 24 centimeters – the sum of the two lengths of the rectangle, since the sum of its other two sides is 8 centimeters, and the perimeter is 32 centimeters;

4) 24: 2 = 12 centimeters – the width of the rectangle.

Answer: 12 centimeters.