The perimeter of the triangle ABC is 88 cm. The sides AB and BC are equal, and the length of the AC side is 32 cm.

The perimeter of the triangle ABC is 88 cm. The sides AB and BC are equal, and the length of the AC side is 32 cm. What are the lengths of the sides AB and BC.

Let the lengths of the sides AB and BC of the triangle ABC be equal in x cm. Knowing the perimeter of this triangle 88 cm, the third side AC = 32 cm and knowing that the perimeter of the triangle is the sum of all sides, we can draw up an equation and solve it:
x + x + 32 = 88;
2x = 88 – 32;
2x = 56;
x = 56/2;
x = 28.
If x = 28, then the lengths of the sides AB and BC are equal to 28 cm.
Answer: 28 cm and 28 cm.
Check:
28 + 28 + 32 = 88;
88 = 88.



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