The perimeter of the triangle is 117 cm. Find its sides if one of them is 7 cm larger
The perimeter of the triangle is 117 cm. Find its sides if one of them is 7 cm larger than the other and 19 cm less than the third.
Let x denote the length of the first side of this triangle.
According to the condition of the problem, the first side of this triangle is 7 cm larger than its other side and 19 cm less than the third side of this triangle, therefore, the lengths of the second and third sides of this triangle are, respectively, x – 7 cm and x + 19 cm.
It is also known that the perimeter of this triangle is 117 cm, therefore, we can draw up the following equation:
x + x – 7 + x + 19 = 117.
We solve the resulting equation and find the length of the first side of this triangle:
3x + 12 = 117;
3x = 117 – 12;
3x = 105;
x = 105/3;
x = 35 cm.
Knowing the length of the first side of a given triangle, we find the lengths of its other two sides:
x – 7 = 35 – 7 = 28 cm;
x + 19 = 35 + 19 = 54 cm.
Answer: the lengths of the side of this triangle are 35 cm, 28 cm and 54 cm