The perimeter of the triangle is 174 mm. One of the sides is 7 times larger than the other and 66 mm

The perimeter of the triangle is 174 mm. One of the sides is 7 times larger than the other and 66 mm smaller than the third. Find the length of the m-sides of the triangle.

Let’s denote by x the length of side number one of this geometric figure.

In the initial data for this task it is reported that side number one of this geometric figure is seven larger than the other and 66 millimeters less than side number three, therefore, the length of side number two is x / 7 mm, and the length of side number three is x + 66 mm …

Also in the condition of the problem it is said that if you add up the lengths of all sides of a given triangle, the result will be 174 mm, therefore, we can draw up the following equation:

x + x / 7 + x + 66 = 174,

solving which, we get:

15x / 7 + 66 = 174;

15x / 7 = 174 – 66;

15x / 7 = 108;

x / 7 = 108/15;

x / 7 = 7.2;

x = 7 * 7.2 = 50.4 mm.

Therefore, the lengths of the sides of this triangle are 50.4 mm, 50.4 / 7 = 7.2 mm, and 50.4 + 66 = 116.4 mm.

Answer: 50.4mm, 7.2mm, 116.4mm.