The perimeter of the triangle is 20 cm. Find its length and width if the length is 8 cm more than the width.

The perimeter of the triangle is: P = 2 * (a + b), (where a is the length, b is the width)

Let width – b be x, so length – a will be (x + 8)

Let’s solve this problem through the equation and substitute these values into the formula:

20 = 2 * (x + x + 8)

20 = 2 * (2x + 8)

20 = 4x + 16

20 – 16 = 4x

4 = 4x

x = 1 – we found the width of the triangle

Now we find the length: x + 8 = 1 + 8 = 9

Answer: length a = 9, width b = 1