The perimeter of the triangle is 28 cm, and one of its sides is 10 cm. Find the lengths of the other two .

The perimeter of the triangle is 28 cm, and one of its sides is 10 cm. Find the lengths of the other two sides if their difference is 2 cm.

As you know, the perimeter of a triangle is the sum of all sides, and is calculated by the following formula: P = a + b + c.
From the problem statement, we know: the perimeter P = 28 cm, one side a = 10 cm, the other side 2 cm shorter b = c + 2 cm.
Substitute all the known values of the sides and perimeter of the triangle into the formula and find the third side: 28 = 10 + s + 2 + s.
28 = 12 + 2s.
2s = 28 – 12 = 16.
c = 16/2 = 8 cm.
b = 8 + 2 = 10 cm.
Answer: the lengths of the second and third sides of the triangle are 8 cm and 10 cm.