The perimeter of the triangle is 52 cm. One of the sides is 4 cm smaller than the other

univerkov | August 10, 2021 | education

The perimeter of the triangle is 52 cm. One of the sides is 4 cm smaller than the other and 3 cm more than the third. Determine the length of each side.

Let the length of the side AB, triangle ABC be equal to X cm.

AB = X cm.

Then, by condition, the length of the BC side = (X + 4) cm, the length of the AC side = (X – 3) cm.

The perimeter of the triangle ABC is:

Ravs = AB + BC + AC = X + (X + 4) + (X – 3) = 52 cm.

3 * X + 1 = 52.

3 * X = 51 cm.

X = AB = 51/3 = 17 cm.

BC = 17 + 4 = 21 cm.

AC = 17 – 3 = 14 cm.

Answer: The sides of the triangle are 14 cm, 17 cm, 21 cm.

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