The perimeter of the triangle is 80 cm. The length of one of its sides is 4 cm longer than the length of the second

| March 2, 2021 | education

The perimeter of the triangle is 80 cm. The length of one of its sides is 4 cm longer than the length of the second, but shorter than the third by 3 cm, find the lengths of the sides.

The solution of the problem:
We will solve the problem using an equation with one unknown.
1. Let’s denote one of the sides of the triangle through x centimeters.
2. Let’s define what is the other side of the triangle.
(x + 4) centimeters.
3. Determine what is the third side of the triangle.
(x + 4) + 3 = x + 4 + 3 = (x + 7) centimeters.
4. Let’s compose and solve the equation.
x + (x + 4) + (x + 7) = 80
x + x + 4 + x + 7 = 80
x + x + x = 80-4-7
3x = 69
x = 69/3
x = 23
5. One side of the triangle is x = 23 cm.
6. The other side is x + 4 = 23 + 4 = 27 cm.
7. The third side is x + 7 = 23 + 7 = 30 cm.
Answer: One side of the triangle = 23 cm. The other = 27 cm. The third = 30 cm.



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