The perimeter of triangle ABC is 15 cm. Side BC is 2 cm larger than side AB, and side AB is 1 cm

The perimeter of triangle ABC is 15 cm. Side BC is 2 cm larger than side AB, and side AB is 1 cm less than side AC. Find the sides of the triangle.

The perimeter is the sum of the lengths of all sides.
Therefore, the perimeter ABC = AB + BC + AC
Let x – BC, then AB = x-2, and AC = x-2 + 1. Let’s make the equation:
x + x-2 + x-2 + 1 = 15
3x – 3 = 15
3x = 18
x = 6
Then AB = 6-2 = 4cm, AC = 6-1 = 5cm
Answer: AB = 4cm, AC = 5cm, BC = 6cm