The perimeter of triangle ABC is 17/20 meters, side AB is exactly 17/50 meters
The perimeter of triangle ABC is 17/20 meters, side AB is exactly 17/50 meters, side BC is 9/50 meters shorter than AB. find the length of the AC side.
Find the length of the side BC of this triangle ABC.
According to the condition of the problem, the length of the AB side is 17/50 meters, and the BC side is 9/50 meters shorter than AB, therefore, the BC side length is:
| BC | = 17/50 – 9/50 = 8/50 = 4/25 m.
Let us find the length of the side AC of this triangle.
According to the condition of the problem, the perimeter of triangle ABC is 17/20 meters, therefore, we can make the following equation:
17/50 + 4/25 + | AC | = 17/20.
We solve the resulting equation:
17/50 + 8/50 + | AC | = 17/20;
25/50 + | AC | = 17/20;
1/2 + | AC | = 17/20;
| AC | = 17/20 – 1/2;
| AC | = 17/20 – 10/20;
| AC | = 7/20 m.
Answer: The length of the AC side is 7/20 m.