The perimeter of triangle ABC is 40 cm. Side BC is 5/7 of side AB, and side AC is 2 cm larger than AB.

The perimeter of triangle ABC is 40 cm. Side BC is 5/7 of side AB, and side AC is 2 cm larger than AB. Finding the side of a triangle ABC

1. If we imagine that AB is equal to x, then BC will be 5x / 7, and AC is equal to 2 + x. Add all the sides to get the perimeter of the triangle. Let’s solve the resulting equation:

x + 5x / 7 + 2 + x = 40,

2x + 5x / 7 = 40 – 2,

14x / 7 + 5x / 7 = 38,

19x / 7 = 38,

19x = 38 * 7,

x = 266/19,

x = 14 cm.

2. Find BC and AC:

BC = 5 * 14/7 = 10 cm.

AC = 2 + 14 = 16 cm.

Answer: AB is 14 cm long, BC is 10 cm, AC is 16 cm.