The perimeter of triangle ABC is 50 cm. Side AB is 2 cm larger than side BC, and side AC

The perimeter of triangle ABC is 50 cm. Side AB is 2 cm larger than side BC, and side AC is 2 times larger than side BC. Find the sides of the triangle.

1. Let’s designate the side of the BC triangle – “X”. Then AB = “X + 2” and AC = “X * 2”. The perimeter of a triangle is the sum of all its sides. Let’s compose and solve the equation:
X + (X + 2) + (X * 2) = 50;
X + X + 2 + 2X = 50;
4X = 50 – 2;
X = 48/4;
X = 12 (cm) is the length of the BC side.
2. Let’s find other sides:
AB = 12 + 2 = 14 (cm);
AC = 12 * 2 = 24 (cm).
Answer: the sides of the triangle are equal: BC = 12 cm, AB = 14 cm, AC = 24 cm.