The perimeter of triangle ABC is 55 cm. The AB side is 3 cm larger than the BC side, and the AC

univerkov | February 25, 2021 | education

The perimeter of triangle ABC is 55 cm. The AB side is 3 cm larger than the BC side, and the AC side is 3 times larger than the BC side. Find the sides of the triangle.

Let the length of the side BC = X cm, then AC = 3 * X cm, and the length of the side AB = (BC + 3) = (X + 3) cm.

The perimeter of the triangle is:

P = AB + BC + AC = 55 cm.

55 = (X +3) + X + 3 * X = 5 * X + 3.

5 * X = 55 – 3 = 52 cm.

X = BC = 52/5 = 10.4 cm.

AB = 10.4 + 3 = 13.4 cm.

AC = 3 * 10.4 = 31.2 cm.

Answer: The sides of the triangle are 10.4 cm, 13.4 cm, 31.2 cm.

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