The perimeter of triangle ABC is 56 cm. Side BC is 4 cm larger than side AB

The perimeter of triangle ABC is 56 cm. Side BC is 4 cm larger than side AB, and side A is 2 times larger than side AB. Find the sides of the triangle.

Conditions of the problem:

ABC perimeter – 56 cm,

Sun -? 4 cm more AB,

AB -? cm,

AC -? 2 times more AB.

x cm – side AB of triangle ABC,

x + 4 – side BC of triangle ABC,

x * 2 – side AC of triangle ABC,

Let’s make an equation and solve it

x + x + 4 + x * 2 = 56,

4 * x = 56 – 4,

4 * x = 52,

x = 52/4,

x = 13 cm side AB of triangle ABC,

13 + 4 = 17 cm BC side of triangle ABC,

13 * 2 = 26 cm AC side of triangle ABC.

Answer: in triangle ABC 13 cm side AB, 17 cm side BC, 26 cm side AC.



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