The perimeter of triangle ABC is 8. find the perimeter of triangle FDE, the vertices of the crown

The perimeter of triangle ABC is 8. find the perimeter of triangle FDE, the vertices of the crown are the midpoints of the sides of triangle ABC.

If points P, D, E are midpoints of sides ∆ ABC, P є AB, D є BC, E є AC, then segments PD, DE, PE are midlines ∆ ABC, PD = 1/2 * AC, DE = 1 / 2 * AB, PE = 1/2 * BC, then the perimeter ∆ PDE is half the perimeter ∆ ABC: 8/2 = 4 (cm).
Answer. The perimeter ∆ PDE is 4 cm.



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