The perimeters of the square and rectangle are equal. Square area 36 m2. The length of the rectangle is 5 times

The perimeters of the square and rectangle are equal. Square area 36 m2. The length of the rectangle is 5 times its width. Find: a) the area of the rectangle b) the perimeter of the rectangle c) the perimeter of the square.

Let’s find the side of the square, knowing its area:

a = √S = √36 = 6 m.

The perimeter of the square is 4 * 6 = 24 m. The same value is the perimeter of the rectangle.

Let’s calculate the sides of the rectangle. Let x be the width, then the length is 5x, knowing the perimeter, we compose the equation:

(x + 5x) * 2 = 24,

6x = 12,

x = 2. This is the width, then the length is 5 * 2 = 10 m.

Now we can answer all the questions of the problem:

a) The area of the rectangle S = 3 * 10 = 30 m2.

b) The perimeter of the rectangle is 24 m.

c) The perimeter of the square is 24 m.