The person walked the path S1 = 10 km in time t1 = 2 hours then rested for t2 = 30 minutes after

| August 12, 2021 | education

The person walked the path S1 = 10 km in time t1 = 2 hours then rested for t2 = 30 minutes after that walked another s3 = 5 km in t3 = 2 hours remembered that he forgot his bag and returned to the place of rest for t4 = 1 hour the remaining s5 L = 15 km people passed in t5 = 90min find the average speed of a person

Task data: S1 (initial path) = 10 km; t1 (start time) = 2 hours; t2 (rest time) = 30 min = 0.5 h; S3 (path from the resting place) = 5 km = S4 (return path); t3 (travel time from the resting place) = 2 hours; t4 (time of the return movement to the place of rest) = 1 hour; S5 (remaining distance) = 15 km; t5 (remaining time) = 90 minutes = 1.5 hours.

To find the value of the average ground speed of the specified person, we apply the formula: Vav = S / t = (S1 + 0 + 2S3 + S5) / (t1 + t2 + t3 + t4 + t5).

Calculation: Vav = (10 + 0 + 2 * 5 + 15) / (2 + 0.5 + 2 + 1 + 1.5) = 5 km / h.

Answer: The average ground speed of the specified person is 5 km / h.



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