The pilot, whose weight is 80 kg, performs a loop with a radius of 250 m. The speed of the aircraft is 540 km / h.

The pilot, whose weight is 80 kg, performs a loop with a radius of 250 m. The speed of the aircraft is 540 km / h. With what force does the pilot press down on the seat of the seat at the lowest point of the hinge?

Task data: m (pilot’s weight) = 80 kg; R (loop radius) = 250 m; V (aircraft speed) = 540 km / h (in SI V = 150 m / s).
Reference values: g (acceleration due to gravity) ≈ 10 m / s2.
The force with which the pilot must press on the seat of the seat at the bottom of the loop is calculated using the formula: F = P = m * (an + g) = m * (V ^ 2 / R + g).
Let’s perform the calculation: F = 80 * (150 ^ 2/250 + 10) = 8000 N (8 kN).
Answer: The pilot will press on the seat with a force of 8 kN.