The plane flew at a speed of 216 km / h. and began to move with an acceleration of 9m / s ^ 2

The plane flew at a speed of 216 km / h. and began to move with an acceleration of 9m / s ^ 2 for 20 seconds, how far did the plane flew during this time and what speed did it reach?

Data: V0 (speed before acceleration) = 216 km / h (in SI system V0 = 60 m / s); a (acceleration) = 9 m / s2; t is the duration of the accelerated movement of the aircraft (t = 20 s).

1) Distance traveled by a given aircraft during accelerated movement: S = V0 * t + a * t ^ 2/2 = 60 * 20 + 9 * 20 ^ 2/2 = 3000 m or 3 km.

2) Final speed: V = V0 + a * t = 60 + 9 * 20 = 240 m / s (864 km / h).

Answer: The given plane flew in 9 seconds a distance of 3 km and reached a speed of 240 m / s.