The plane flew for 30 minutes at a speed of 450 km / h, then 200 km at a speed of 500 km / h.

The plane flew for 30 minutes. at a speed of 450 km / h, then 200 km at a speed of 500 km / h. Determine: a) distance traveled b) average speed

Distance traveled:
S = V1 * t1 + V2 * t2, where V1 = 450 km / h, t1 = 30 min = 0.5 h, V2 = 500 km / h, t2 = S2 / V2 (S2 = 200 km).
Let’s calculate the distance traveled:
S = V1 * t1 + V2 * t2 = V1 * t1 + S2 = 450 * 0.5 + 200 = 425 km.
Average travel speed:
Vav. = S / t, where t is the total time of movement (t = t1 + t2).
Vav. = S / t = S / (t1 + t2) = S / (t1 + S2 / V2) = 425 / (0.5 + 200/500) = 425 / 0.9 = 472.2 km / h.
Answer: The distance covered is 425 km, the average speed is 472.2 km / h.