The plane flew from point A to point B at a speed of 750 km / h, and back from B to A-at a speed of 1000 km / h

The plane flew from point A to point B at a speed of 750 km / h, and back from B to A-at a speed of 1000 km / h. Find the average speed of the A-B-A route

Let’s write the distance between point A and point B as 1.

In this case, the conditional flight time will be equal to the ratio of distance and speed.

1/750 = 1/750 hour.

On the way back:

1/1000 = 1/1000 hour.

We find the total time spent for the entire journey.

Let’s summarize the obtained values.

1/750 + 1/1000 = 4/3000 + 3/3000 = 7/3000 hours.

The total distance will be equal to:

1 + 1 = 2.

Find the average speed.

We divide the entire distance by time.

We get:

2/7/3000 = 2 * 3000/7 = 6000/7 = 857 1/7 km / h.

Answer: 857 1/7 km / h.