The plane flies at an altitude of 500 m at a speed of 72 km / h. A pennant is being ejected from the plane.

The plane flies at an altitude of 500 m at a speed of 72 km / h. A pennant is being ejected from the plane. How far will it fall?

To calculate the distance at which the pennant will fall, use the formula: S = V * t = V * √ (2h / g).

Variables and constants: V – speed (horizontal) of the aircraft (V = 72 km / h; in SI V = 20 m / s); h – height (h = 500 m); g – acceleration due to gravity (g ≈ 0 m / s2).

Let’s make a calculation: S = V * √ (2h / g) = 20 * √ (2 * 500/10) = 200 m.

Answer: The pennant will fall at a distance of 200 m from the point of release from the aircraft.