The plane flies horizontally at a speed of 360 km / h at an altitude of 490m. When it flies over point A

The plane flies horizontally at a speed of 360 km / h at an altitude of 490m. When it flies over point A, a packet is dropped from it. At what distance from point A will the packet fall to the ground?

To calculate the distance from point A at which the dropped packet will fall, we apply the formula: S = V * t = V * √ (2h / g).

Constants and variables: V – horizontal speed of the aircraft (V = 360 km / h; in SI V = 100 m / s); h – height (h = 490 m); g – acceleration due to gravity (g = 9.8 m / s2).

Let’s calculate: S = V * √ (2h / g) = 100 * √ (2 * 490 / 9.8) = 1000 m.

Answer: The package will fall to the ground at a distance of 1000 meters from point A.



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