The plane flies horizontally at an altitude of 8 km at a speed of 1800 km / h.

The plane flies horizontally at an altitude of 8 km at a speed of 1800 km / h. How many kilometers before the target should the pilot drop the bomb to hit the target?

Given:

v = 1800 km / h = 500 m / s – aircraft speed;

H = 8 kilometers = 8000 meters – the altitude at which the plane is flying;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to find L (kilometers) – the distance to the target when you need to drop the bomb to hit the target.

The dropped bomb will move at the same speed as the plane. Let’s find the flight time of the bomb:

t = (2 * H / g) ^ 0.5 = (2 * 8000/10) ^ 0.5 = (1600) ^ 0.5 = 40 seconds.

During this time, in the horizontal direction, the bomb will have time to fly the distance L:

L = v * t = 500 * 40 = 20,000 meters = 20 kilometers.

Answer: the pilot must drop the bomb 20 kilometers before the target.