# The plane flying in the horizontal direction is affected by the direction of flight, the thrust

**The plane flying in the horizontal direction is affected by the direction of flight, the thrust force of the engine F = 15000 and the force of air resistance FC = 11000 N and the force of the crosswind pressure FB = 3000 N, the direction at an angle of 90 degrees to the course. Find the resultant of these forces.**

Data: F (thrust force of the aircraft engine) = 15000 N; Fc (air resistance force) = 11000 N; Fb (crosswind pressure force) = 3000 N; the crosswind pressure vector is directed at an angle of 90º to the heading.

1) Let us determine the resultant force that acts in the direction of the aircraft’s course: F = Fc + Fb = 15000 – 11000 = 4000 N.

2) Calculate the total resultant of all forces (Pythagorean theorem): Fр = √ (F ^ 2 + Fb ^ 2) = √ (4000 ^ 2 + 3000 ^ 2) = 5000 N (5 kN).

Answer: The resultant of all given forces is 5 kN.