The plane flying in the horizontal direction is affected by the direction of flight, the thrust

The plane flying in the horizontal direction is affected by the direction of flight, the thrust force of the engine F = 15000 and the force of air resistance FC = 11000 N and the force of the crosswind pressure FB = 3000 N, the direction at an angle of 90 degrees to the course. Find the resultant of these forces.

Data: F (thrust force of the aircraft engine) = 15000 N; Fc (air resistance force) = 11000 N; Fb (crosswind pressure force) = 3000 N; the crosswind pressure vector is directed at an angle of 90º to the heading.

1) Let us determine the resultant force that acts in the direction of the aircraft’s course: F = Fc + Fb = 15000 – 11000 = 4000 N.

2) Calculate the total resultant of all forces (Pythagorean theorem): Fр = √ (F ^ 2 + Fb ^ 2) = √ (4000 ^ 2 + 3000 ^ 2) = 5000 N (5 kN).

Answer: The resultant of all given forces is 5 kN.