The plane lit at a speed of 216 km / h and began to move with an acceleration

The plane lit at a speed of 216 km / h and began to move with an acceleration of 9 m2 / s for 20 seconds to find the distance that the plane arrived.

Problem data: V0 (initial aircraft speed) = 216 m / s (in the SI system V0 = 60 m / s); a (acceleration) = 9 m / s2; t (duration of the accelerated movement of the aircraft) = 20 s.

The distance that the plane managed to cover during its accelerated movement is calculated by the formula: S = V0 * t + a * t ^ 2/2.

Let’s perform the calculation: S = 60 * 20 + 9 * 20 ^ 2/2 = 3000 m (3 km).

Answer: During its accelerated movement, the plane flew 3 km.



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