The plane passes 6 cm from the center of the ball. The section radius is 10 cm. Find the area of the sphere.

One side of the triangle is 46.3 cm, the other is 16.7 cm less than the first and 14.8 cm less than the third. Find the perimeter of the triangle.

By the Pythagorean theorem, we find the area of the radius of the sphere R ^ 2 = 10 ^ 2 + 6 ^ 2 = 136
S = 4 * pi * R ^ 2 = 544 * pi
By the Pythagorean theorem, we find the area of the radius of the sphere R ^ 2 = 10 ^ 2 + 6 ^ 2 = 136
S = 4 * pi * R ^ 2 = 544 * pi



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